ECON 376
Widely applied GRAVITY MODEL: Reilly’s Law
for estimating the mile radius of the exclusive market area around a place.
Consider places i,j = A,B,C,D and E, with r = location of a customer along the road between places. The distances between these places:
|
|
A |
B |
C |
D |
E |
|
POPi |
100 |
80 |
50 |
200 |
75 |
|
dAj |
0 |
20 |
10 |
30 |
40 |
Reilly’s Law: mi(j) =
|
POPj/POPA |
1 |
0.8 |
0.5 |
2.0 |
0.75 |
|
Ö |
|
0.89 |
0.7 |
1.41 |
.86 |
|
+1 |
|
1.89 |
1.7 |
2.41 |
1.86 |
|
dAj ∙/∙ = mA( j) |
|
10.5 |
5.9 |
12.5 |
21.5 |
Thus, we can easily calculate the
distances from place A, in the directions toward places B,C,D, and E, of the
extent of A’s market area. All we need to know are the map distances between
the places, and the populations. In the
illustration, Place A’s market area is shaded yellow.
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Deriving
Reilly’s Law from the physical law of gravity:
Fundamentally: The gravitational
attraction between two places is directly proportional to their masses and
inversely proportional to the (square of the) distance between them:
1 =
POPi/POPj
x (drj/dri)2
where dri+drj=dij
We can express the distance from
a customer at site r to place j (drj) as drj=dij-dri
Reilly’s Law will help us find
the farthest site r, at distance m from place i at which a customer will
shop at place i. So, we want to find
the “dri*” which is the same thing as the radius of the market area
around i, so we can label dij as m
i(j) . Rewriting the fundamental
formula using m and dij -m in place of dri and drj,
we have:
1 =
(POPi/POPj)(dij –m)/m)2
rearranging this expression to
solve for m, we have:
mi(j)
=
Done!